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6y^2-37y+22=0
a = 6; b = -37; c = +22;
Δ = b2-4ac
Δ = -372-4·6·22
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-29}{2*6}=\frac{8}{12} =2/3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+29}{2*6}=\frac{66}{12} =5+1/2 $
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